3x+4y-z=4,2x+3y+2z=11,6x-2y+2z=10

x+2y=3x+2z=4y+z 求x:y:z x+y/2=z+x/3=y+z/4 x+y+z=27 2x+z=10 x+y-z=4 3x-y-z=0 x=y/z=z/3,x+y+z ＝12,求2x+3y+4z是多少, 4x+y+z=-3 2x+3y-4z=-10 x+2y-z=-1 x+y+z=2 4x+2y+z=4 2x+3y+z=1 x-y-z=1 2x+y-3z=4 3x-2y-z=-1 x+y-z=6 x-3y+2z=1 3x+2y-z=4 阿 x+y-z=6,x-3y+2z=1,3x+2y-z=4 x+y+z=-5,3x+y+z=1,4x+3y+2z=-2快 3x+2y+z=4 x+y+z=10 2x+3y-z=1 x+y-z=6 x-3y+2z=1 3x+2y-z=4 3X+Y+Z=0,2X-Y+3Z=1,X+2Y-Z=4 3x-y+2z=-1 4x+y+z=5 x-2y-z=-2 {3X+2Y+Z=4X+Y+Z=102X+3Y-Z=1 x+y-z=6 x-3y+2z=1 3x+y-z=4 x-y+z=-1 5x+2y-z=6 4x-3y+2z=-5 x+y+z=-1 4x-2y+3z=5 y-z=8-2x