如果(x²+y²)(x²+y²-10)+25=0,求x²+y²的值

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如果(x²+y²)(x²+y²-10)+25=0,求x²+y²的值如果(x²+y²)(x²+y²-1

如果(x²+y²)(x²+y²-10)+25=0,求x²+y²的值
如果(x²+y²)(x²+y²-10)+25=0,求x²+y²的值

如果(x²+y²)(x²+y²-10)+25=0,求x²+y²的值
(x²+y²)(x²+y²-10)+25=0
(x²+y²)²－10(x²+y²)＋25=0
(x²+y²－5)²=0
所以x²+y²－5=0
x²+y²=5