关于复合函数求导√((x-1)/(x+1))

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关于复合函数求导√((x-1)/(x+1))关于复合函数求导√((x-1)/(x+1))关于复合函数求导√((x-1)/(x+1))y=√((x-1)/(x+1))t=(x-1)/(x+1)√((x-

关于复合函数求导√((x-1)/(x+1))
关于复合函数求导
√((x-1)/(x+1))

关于复合函数求导√((x-1)/(x+1))
y=√((x-1)/(x+1))
t=(x-1)/(x+1)
√((x-1)/(x+1)) =√t
y't=1/[2√t]
t'x=[(x+1)-(x-1)]/(x+1)^2
=2/(x+1)^2
y"x=y't*t'x=1/[2√t]*2/(x+1)^2
=1/[√(x^2-1)*(x+1)]