(x^2+y)(x^2-Y)-(-x)^2*(-x^2) 已知2^48-1可以被60到70之间的某两个整数整除,求这两个数是多少还有

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(x^2+y)(x^2-Y)-(-x)^2*(-x^2)已知2^48-1可以被60到70之间的某两个整数整除,求这两个数是多少还有(x^2+y)(x^2-Y)-(-x)^2*(-x^2)已知2^48-

(x^2+y)(x^2-Y)-(-x)^2*(-x^2) 已知2^48-1可以被60到70之间的某两个整数整除,求这两个数是多少还有
(x^2+y)(x^2-Y)-(-x)^2*(-x^2) 已知2^48-1可以被60到70之间的某两个整数整除,求这两个数是多少
还有

(x^2+y)(x^2-Y)-(-x)^2*(-x^2) 已知2^48-1可以被60到70之间的某两个整数整除,求这两个数是多少还有
(x^2+y)(x^2-Y)-(-x)^2*(-x^2)
=x^4-y²+x^4
=2x^4-y²

已知2^48-1可以被60到70之间的某两个整数整除,求这两个数是多少
2^48-1
=(2^24+1)(2^24-1)
=(2^24+1)(2^12+1)(2^12-1)
=(2^24+1)(2^12+1)(2^6+1)(2^6-1)
∴能被2^6+1及2^6-1
即65和63整除

(x^2+y)(x^2-y)-(-x)^2*(-x^2)
=x^4-y^2-x^2*(-x^2)
=x^4-y^2+x^4
=2x^4-y^2
2^48-1
=(2^24-1)(2^24+1)
=(2^12-1)(2^12+1)(2^24+1)
=(2^6-1)(2^6+1)(2^12+1)(2^24+1)
=63*65*(2^12+1)(2^24+1)
2^48-1可以被60到70之间的某两个整数整除，求这两个数是：63和65

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