化简:1/2x-1/(x+y).[(x+y)/2 - (2x²+2xy)/2x]
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化简:1/2x-1/(x+y).[(x+y)/2-(2x²+2xy)/2x]化简:1/2x-1/(x+y).[(x+y)/2-(2x²+2xy)/2x]化简:1/2x-1/(x+y
化简:1/2x-1/(x+y).[(x+y)/2 - (2x²+2xy)/2x]
化简:1/2x-1/(x+y).[(x+y)/2 - (2x²+2xy)/2x]
化简:1/2x-1/(x+y).[(x+y)/2 - (2x²+2xy)/2x]
原式=1/2x-1/(x+y).[(x+y)/2- (x+y)/2]
=1/2x-1/(x+y).0
=1/2x
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