x/2=y/3=z/4 x+y+z=18 求方程组解

来源：学生作业帮助网编辑：六六作业网时间：2025/01/11 12:19:24

x/2=y/3=z/4x+y+z=18求方程组解x/2=y/3=z/4x+y+z=18求方程组解x/2=y/3=z/4x+y+z=18求方程组解设x/2=y/3=z/4＝K则x=2Ky=3Kz=4K原

x/2=y/3=z/4 x+y+z=18 求方程组解
x/2=y/3=z/4 x+y+z=18 求方程组解

x/2=y/3=z/4 x+y+z=18 求方程组解
设x/2=y/3=z/4＝K
则 x=2K y=3K z=4K
原方程就变成 2K+3K+4K=18
所以 K=2
则 x=4 y=6 z=8

X=4,Y=6,Z=8
解法一
由X/2=Y/3=Z/4得,设X/2=Y/3=Z/4=K
则Y=3K X=2K Z=4K 带入下式
9K=18
K=2
所以 X=4 Z=8 Y=6
解法二
设X=1/6K，Y=1/4K,z=1/3K(据1式变形)
则1/6K+1/4K+1/3K=18，K=24
所以X=4，Y=6，Z=8

设x/2=y/3=z/4＝k
所以x＝2k， y＝3k, z=4k
代入方程2
2k+3k+4k=18, k=2
所以 x=2*2=4, y＝3*2=6, z=4*2=8

x+y/2=z+x/3=y+z/4 x+y+z=27 x+2y=3x+2z=4y+z 求x:y:z 已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z 试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y) 已知实数x y z满足x/(x+1)=y/(y+2)=z/(z+3)=(x+y+z)/3,求x+y+z的值已知实数x y z满足x/(x+1)=y/(y+2)=z/(z+3)=(x+y+z)/3,求x+y+z的值 x+y+z=6 x+2y+3z=14 y+1=z 2x+z=10 x+y-z=4 3x-y-z=0 已知 x/(y+z)+y/(z+x)+z/(x+y)=1求 (x*x)/(y+z)+(y*y)/(x+z)+(z*z)/(x+y)=? x=y/z=z/3,x+y+z ＝12,求2x+3y+4z是多少, 若|x+3|+|y-2|+|2×z+1|=0求(x×z-y×z)(y-x+z)的值 4x+y+z=-3 2x+3y-4z=-10 x+2y-z=-1 x-y-z=1 2x+y-3z=4 3x-2y-z=-1 x+y+z=2 4x+2y+z=4 2x+3y+z=1 x+y-z=6 x-3y+2z=1 3x+2y-z=4 阿 x+y-z=6,x-3y+2z=1,3x+2y-z=4 x+y+z=-5,3x+y+z=1,4x+3y+2z=-2快 3x+2y+z=4 x+y+z=10 2x+3y-z=1