∫{x^2/[(x-3)(x+2)^2]}dx
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∫{x^2/[(x-3)(x+2)^2]}dx∫{x^2/[(x-3)(x+2)^2]}dx∫{x^2/[(x-3)(x+2)^2]}dxx^2/[(x-3)(x+2)^2=(9/25)[1/(x-3
∫{x^2/[(x-3)(x+2)^2]}dx
∫{x^2/[(x-3)(x+2)^2]}dx
∫{x^2/[(x-3)(x+2)^2]}dx
x^2/[(x-3)(x+2)^2=(9/25)[1/(x-3)]+(16/25)[1/(x+2)]-(20/25)[1/(x+2)^2].
原式=(9/25)∫1/(x-3)dx+(16/25)∫1/(x+2)dx-(4/5)∫1/(x+2)^2dx
=(9/25)ln|x-3|+(16/25)ln|x+2|+(4/5)[1/(x+2)]+C.
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