4xy+1-4x^2-y^2= x^6-y^6-2x^3+1= x^4+64= x^3-4xy^2-2x^2y+8y^3=

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4xy+1-4x^2-y^2=x^6-y^6-2x^3+1=x^4+64=x^3-4xy^2-2x^2y+8y^3=4xy+1-4x^2-y^2=x^6-y^6-2x^3+1=x^4+64=x^3-4

4xy+1-4x^2-y^2= x^6-y^6-2x^3+1= x^4+64= x^3-4xy^2-2x^2y+8y^3=
4xy+1-4x^2-y^2= x^6-y^6-2x^3+1= x^4+64= x^3-4xy^2-2x^2y+8y^3=

4xy+1-4x^2-y^2= x^6-y^6-2x^3+1= x^4+64= x^3-4xy^2-2x^2y+8y^3=
我高中数学老师、
应该是这样没错
4xy+1-4x^2-y^2=1-(4x^2-4xy+y^2)=1-(2x-y)^2=(1+2x-y)(1+y-2x)
x^6-y^6-2x^3+1= x^6-x^3-x^3+1-y^6=x^3(x^3-1)-(x^3-1)-y^6=(x^3-1)^2-y^6
=(x^3-1-y^3)(x^3-1+y^3)
x^4+64=x^4+16x^2+64-16x^2=(x^4+16x^2+64)-16x^2=(x^2+8)^2-16x^2=
(x^2+8-4x)(x^2+8+4x)
x^3-4xy^2-2x^2y+8y^3=(x^3+8y^3)-2xy(2y+x)=(x+2y)(x^2-2xy+4y^2)-2xy(x+2y)=(x+2y)(x^2-4xy+4y^2)=(x+2y)(x-2y)^2

1-2/x+y=xy,4y+6x=xy.求xy的解? 已知1/x-1/y=2,求3x+7xy-3y/2x-3xy-2y答案是1/x-1/y=2(y-x)/xy=2 得：x-y=-2xy(3x+7xy-3y)/(2x-3xy-2y)=[3(x-y)+7xy]/[2(x-y)-3xy]=(-6xy+7xy)/(-4xy-3xy)=xy/(-7xy)=-1/7 谁能帮我解释一下=[3(x-y)+7xy]/[2(x-y)-3xy]=(-6xy+7xy)/(-4xy-3xy) 是怎化简求值x-4y/2x-7xy+3y×x-2xy-3y/2x+3xy-2y÷3x-6y/4x-4xy+y,其中：x=1999,y=-1 4xy-[(x²+5xy-y²)-(3xy-1/2y)]x=3,y=-6 -3(2x-xy)-4(-6+xy+x.其中x=1,y=-1 已知x-y=6,xy=-1,求(2x+3x-2xy)-(x+4y+xy)-(3yx-2x+2y)的值 (1)已知x+y=6,xy=-3,x^2y+xy^2=(2)x*[2-(1/x)]+(x/x^2-2x)*(x^2-4) 2x^+xy-y^-4x+5y-6=? 已知2/x-1/y=3,则(2y-x+4xy)/(3x-6y-5xy)=? 诺x+y=6,xy=4 求(5x-4y-3xy)-(8x-y+2xy) (x+y)(x+y+2xy)+(xy+1)(xy-1)(x+y)(x-y)+4(y-1) 已知1/x - 1/y = 2,求3x+7xy-3y / 2x-3xy-2y的值1/x-1/y=2(y-x)/xy=2 得：x-y=-2xy(3x+7xy-3y)/(2x-3xy-2y)=[3(x-y)+7xy]/[2(x-y)-3xy]=(-6xy+7xy)/(-4xy-3xy)=xy/(-7xy)=-1/71/x-1/y=2到(y-x)/xy=2 是怎么变化的.. (-2xy+2x+5y)-(3xy+2y-2x)-(x+4y+xy)其中x-y=4xy=-1 若x-y=4,xy=1,求(-2xy+2x+3y)-(3xy+2y-2x)-(x+4y+xy)的值若x-y=4,xy=1,则(2x+y-2xy)-(3x+2y+xy)-(4xy+3y-5x)= x^+2xy+y^+4=16 x^-2xy+y^=16 求(3xy+6y^)+|x^-(2xy+2y^-3x^)|的值 x-y=1,xy=2.求：(-2xy+2x+3y)-(3xy+2y-2x)-(x+4y+xy)的值 .已知:x-y=1,xy=-2.求:(-2xy+2 x+3y)-(3xy+2y-2x)-(x+4y+xy)的值