若x-y=4,xy=1,则(2x+y-2xy)-(3x+2y+xy)-(4xy+3y-5x)=
来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/22 00:56:11
若x-y=4,xy=1,则(2x+y-2xy)-(3x+2y+xy)-(4xy+3y-5x)=若x-y=4,xy=1,则(2x+y-2xy)-(3x+2y+xy)-(4xy+3y-5x)=若x-y=4
若x-y=4,xy=1,则(2x+y-2xy)-(3x+2y+xy)-(4xy+3y-5x)=
若x-y=4,xy=1,则(2x+y-2xy)-(3x+2y+xy)-(4xy+3y-5x)=
若x-y=4,xy=1,则(2x+y-2xy)-(3x+2y+xy)-(4xy+3y-5x)=
(2x+y-2xy)-(3x+2y+xy)-(4xy+3y-5x)
=2x+y-2xy-3x-2y-xy-4xy-3y+5x
=4x-4y-7xy
=4(x-y)-7xy
因为x-y=4,xy=1
所以
原式=4*4-7=16-7=9
x-y=4, xy=1
∴(2x+y-2xy)-(3x+2y+xy)-(4xy+3y-5x)
=2x+y-2xy-3x-2y-xy-4xy-3y+5x
=4x-4y-6xy
=4﹙x-y﹚-6xy
=4× 4-6×1
=10.
=2x+y-2xy-3x-2y-xy-4xy-3y+5x
=4x-4y-7xy
=4(x-y)-7xy
因为x-y=4,xy=1,所以原式=4*4-7*1=9
若x-y=4,xy=1,则(2x+y-2xy)-(3x+2y+xy)-(4xy+3y-5x)=
若(2x-14xy-2y)除以(x-2xy-y)=4,则1/x-1/y=
若x-y=4,xy=1,求(-2xy+2x+3y)-(3xy+2y-2x)-(x+4y+xy)的值
若x+y=-1,则x^4+5x^3y+x^2y+8x^2y^2+xy^2+5xy^3+y^4=( )若x+y=-1,则x^4+5x^3y+x^2y+8x^2y^2+xy^2+5xy^3+y^4=( )
若1/x-1/y=2,求3x-2xy-3y/x-xy-y的值3x-2xy-3y/x-xy-y 不好意思,是3x-2xy-3y/x-2xy-y
若|x-3|+(y+2)=0,则(x-y+4xy/x-y)(x+y-4xy/x+y)的值是
若|x-3|+(y+2)²=0,则(x-y+4xy/x-y)(x+y-4xy/x+y)的值是
若x+y=1,x不等于0则x+(2xy+y^2)/x/(x+y)/x=
若(x*x+y*y)(x*x+y*y)-4x*x*y*y=0,求代数式(x*x+5xy+y*y)/(x*x+2xy+y*y)的值
若x-y/x+y=2,则x2+2xy+y2/4xy=多少
若x-y=1,xy=5,则x^2y-xy^2=
若1/X-1/Y=3,则2X+XY-2Y/X-2XY-Y=?
若x/1-y/1=5,则x-2xy-y/2x+5xy-2y=?
若x+y=10 xy=-1 则x²+y²=(x+y)²-2xy=
若1/x+1/y=2,则(2x-xy+2y)÷(3x+5xy+3y)
已知2/x-1/y=3,则(2y-x+4xy)/(3x-6y-5xy)=?
已知x+y=1,xy=-2,则x²y+xy²-2xy
若1/x-1/y=2,则(3x+xy-3y)/(x-xy-y)的值为?