若(2x-14xy-2y)除以(x-2xy-y)=4,则1/x-1/y=
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若(2x-14xy-2y)除以(x-2xy-y)=4,则1/x-1/y=若(2x-14xy-2y)除以(x-2xy-y)=4,则1/x-1/y=若(2x-14xy-2y)除以(x-2xy-y)=4,则
若(2x-14xy-2y)除以(x-2xy-y)=4,则1/x-1/y=
若(2x-14xy-2y)除以(x-2xy-y)=4,则1/x-1/y=
若(2x-14xy-2y)除以(x-2xy-y)=4,则1/x-1/y=
(2x-14xy-2y)除以(x-2xy-y)=4
(2x-14xy-2y)=4(x-2xy-y)
2x+6xy-2y=0
x-y=-3xy
两边同除以xy,得
1/y-1/x=-3
所以
1/x-1/y=3
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代数 x^-y^/ x^-(y-z)^ 除以 x^+2xy+y^/(x-y)^-z^ 乘 x^+xy-xz/x^-xy
若(2x-14xy-2y)除以(x-2xy-y)=4,则1/x-1/y=
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化简:(x-y)除以(根号x+根号y)-(x-2根号xy+y)除以(根号x-根号y)