(x+1)4+(x2-1)2+(x-1)4=

来源：学生作业帮助网编辑：六六作业网时间：2024/12/24 21:35:16

(x+1)4+(x2-1)2+(x-1)4=(x+1)4+(x2-1)2+(x-1)4=(x+1)4+(x2-1)2+(x-1)4=(x+1)^4+(x^2-1)^2+(x-1)^4=(x+1)^4+

(x+1)4+(x2-1)2+(x-1)4=
(x+1)4+(x2-1)2+(x-1)4=

(x+1)4+(x2-1)2+(x-1)4=
(x+1)^4+(x^2-1)^2+(x-1)^4
=(x+1)^4+(x+1)^2(x-1)^2+(x-1)^4
=[(x+1)^4+2(x+1)^2(x-1)^2+(x-1)^4]-(x+1)^2(x-1)^2
=(x +1+x-1)^2-(x^2-1)^2
=(2x)^2-(x^2-1)^2
=(2x+(x^2-1))(2x-(x^2-1))
=-(x^2+2x-1)(x^2-2x+1)
=-(x-1)^2(x^2+2x-1)

3/x2 -3x+2-1/x-2=1/x2 -x+4/x2 -2x 通分 3x/x2-2x,2x+1/4-x2,3/2x2+4x (x2+4x)/(x-1) 计算:x2-5x+6/x2-4x+3 + x2-4x+3/x2-2x+1 + x2-3x-4/1-x2 因式分解 (x2+2x)2+2x2+4x+1 证明:根号(x2+2x+4)-根号(x2-x+1) (x+1)(x2-x+1)+(x-2)(x2+2x+4),其中x=-3/2 （x+2)(x2-2x+4)+（x-1)(x2+x+1),其中x=-三分之二先化简,再求值：（4x2-3x)-2（x2+2x-1)-（x2+x-1) 分解因式:4(3x2-x-1)(x2+2x-3)-(4x2+x-4)2 (X2-X)2+(X2+3X+2)2-4(X2+X+1)2因式分解分式计算：2x/x2-x-2÷（1-x/x+1）-x2+2x/x2-4 分式计算：2x/x2-x-2÷（1-x/x+1）-x2+2x/x2-4 化简x/x2+x除以x2+x-2/x2-1+x+1/x+2 1/(x2+x)+1/(x2+3x+2)+1/(x2+5x+6)+1/(x2+7x+12)=4/21x2是x的平方 x2-4x+3分之x2-5x+6+s2-2x+1分之x2-4x+3+1-x2分之x2-3x-4的过程 x2+2x+2/(x+1)=(x2+4x+6)/(x+2)-1 解方程x-4/x2+x-2=1/(x-1)+(x-6)/(x2-4)