求(sin(x∧2sin(1/x)))/x当x→0时的极限
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求(sin(x∧2sin(1/x)))/x当x→0时的极限求(sin(x∧2sin(1/x)))/x当x→0时的极限求(sin(x∧2sin(1/x)))/x当x→0时的极限极限在-1和1之积摆动,极
求(sin(x∧2sin(1/x)))/x当x→0时的极限
求(sin(x∧2sin(1/x)))/x当x→0时的极限
求(sin(x∧2sin(1/x)))/x当x→0时的极限
极限在-1和1之积摆动,极限不存在.
lim(x->0) sin(x²sin(1/x))/x (0/0型)
=lim 2xsin(1/x)cos(x²sin(1/x))-cos(1/x)cos(x²sin(1/x))
=lim 2*0*sin(1/x)cos(0)-cos(1/x)cos(0)
=lim -cos(1/x)
=-cos(∽)
极限不存在!
傅里叶级数作图f(x)=2sin[x] - sin[2x] + 2/3sin[3x] - 1/2sin[4x]我用mathematica输入程序Plot[{2sin[x],-2sin[x],2sin[x] - sin[2x],-2sin[x] + sin[2x],2sin[x] - sin[2x] + 2/3sin[3x],-2sin[x] + sin[2x] - 2/3sin[3x],2sin[x] - sin[2x] + 2/3si
求(sin(x∧2sin(1/x)))/x当x→0时的极限
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