求积分∫(x^4+1)/x^2(x-1)dx,请朋友说下过程吧,
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/23 08:19:01
求积分∫(x^4+1)/x^2(x-1)dx,请朋友说下过程吧,求积分∫(x^4+1)/x^2(x-1)dx,请朋友说下过程吧,求积分∫(x^4+1)/x^2(x-1)dx,请朋友说下过程吧,答:∫{
求积分∫(x^4+1)/x^2(x-1)dx,请朋友说下过程吧,
求积分∫(x^4+1)/x^2(x-1)dx,请朋友说下过程吧,
求积分∫(x^4+1)/x^2(x-1)dx,请朋友说下过程吧,
答:
∫{(x^4+1)/[(x-1)x^2]}dx
=∫[x^2/(x-1)]dx+∫{1/[(x-1)x^2]}dx
=∫[(x-1+1)^2/(x-1)]dx+∫[1/(x-1)]dx-∫[(x+1)/x^2]dx
=∫[x+1+1/(x-1)]dx+∫[1/(x-1)]d(x-1)-∫(1/x+1/x^2)dx
=(1/2)x^2+x+2*ln|x-1|-ln|x|+1/x+C
=(1/2)x^2+x+1/x+ln|(x-1)^2/x|+C
求积分 1/(4x-x^2)
x^2/(1+x) 求积分
求积分:积分号(x^2+1)/(x *(根号下x^4+1)) dx
∫(x^2+1)/(x^4+1)dx求积分?
求积分∫(2x^4+x^3+x-1)/(x^3-1)dx
求积分:∫x/(1-x)dx
求x/(x-1)(x-2)(x-3)积分
x/(1+x^4)求积分
x^2/(1+x^2)求积分
求积分x/(x^2+1)
求(x+1)(x-2)^10 积分
求定积分∫(4,-2)|1-x|dx
求积分(1+x^2)^0.5
积分∫x/[(x^2+1)(x^2+4)]dx
求定积分∫(dx)/(x+(1-x^2)^1/2),积分上限是1,积分下限是0,
4x/(x^2+1)(x+1)积分?
改变二次积分的积分次序求积分.∫1 ~2 dx ∫(2-x)~(√2x-x^2)f(x,y)dy
求积分∫(arctan(1/x)/(1+x^2))dx