若x+2y+3x>=0,则(x+1)^2+(y+2)^2的最小值是?
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若x+2y+3x>=0,则(x+1)^2+(y+2)^2的最小值是?若x+2y+3x>=0,则(x+1)^2+(y+2)^2的最小值是?若x+2y+3x>=0,则(x+1)^2+(y+2)^2的最小值
若x+2y+3x>=0,则(x+1)^2+(y+2)^2的最小值是?
若x+2y+3x>=0,则(x+1)^2+(y+2)^2的最小值是?
若x+2y+3x>=0,则(x+1)^2+(y+2)^2的最小值是?
x+2y+3x>=0
即2x+y≥0
(x+1)^2+(y+2)^2
=(2x+2)^2/4+(y+2)^2
≥(2x+2+y+2)^2/(4+1)(柯西不等式定理)
≥16/5
过点A(-1,-2)作AB垂直于直线x+2y+3=0,①垂足为B,则
AB:2x-y=0.②
由①、②,x=-6/5,y=-3/5,
∴B(-6/5,-3/5),
∴若x+2y+3>=0,则(x+1)^2+(y+2)^2的最小值是AB^2=1/25+49/25=2.
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