若(2x-y+7)^2+|4X+3Y-1|=0,则x^y=___
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若(2x-y+7)^2+|4X+3Y-1|=0,则x^y=___若(2x-y+7)^2+|4X+3Y-1|=0,则x^y=___若(2x-y+7)^2+|4X+3Y-1|=0,则x^y=___(2x-
若(2x-y+7)^2+|4X+3Y-1|=0,则x^y=___
若(2x-y+7)^2+|4X+3Y-1|=0,则x^y=___
若(2x-y+7)^2+|4X+3Y-1|=0,则x^y=___
(2x-y+7)^2+|4X+3Y-1|=0
2x-y+7=0
4x+3y-1=0
x=-2,y=3
x^y=(-2)^3=-8
(2x-y+7)^2+|4X+3Y-1|=0
所以2x-y+7=0 4X+3Y-1=0
x=-2 y=3 x^y=-8
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