x/(y+z)=1/8,z/(x+y)=1/5解得x/z=2/3
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x/(y+z)=1/8,z/(x+y)=1/5解得x/z=2/3x/(y+z)=1/8,z/(x+y)=1/5解得x/z=2/3x/(y+z)=1/8,z/(x+y)=1/5解得x/z=2/3看结果只
x/(y+z)=1/8,z/(x+y)=1/5解得x/z=2/3
x/(y+z)=1/8,z/(x+y)=1/5解得x/z=2/3
x/(y+z)=1/8,z/(x+y)=1/5解得x/z=2/3
看结果只要消元y,应该可以.
第一式有y=8x-z,代入第二式
(x+8x-z)/z=5
9x/z-1=5
x/z=6/9 = 2/3
首先
8x=y+z
5z=x+y
然后把y代掉得到5z=x+(8x-z)
从而6z=9x,最后解得x/z=2/3
已知 x/(y+z)+y/(z+x)+z/(x+y)=1求 (x*x)/(y+z)+(y*y)/(x+z)+(z*z)/(x+y)=?
(x+y-z)(x-y+z)=
(x+y+z)÷10=x+1.1 y+x=z-80+y-1 z-y=8x+y+8 x+z÷y=?
X+Y+Z=?
x/y=(x+z)/(y+z)y/z=(x+y)/(x+z)
{x+y+z=1;x+3y+7z=-1;z+5y+8z=-2
x-y-z=0 4x+8y+z=17 z=1
{X+y+z=8,X一z=-2,y十z=1
(y+z)/x=(z+x)/y=(x+y)/z求x+y-z/x+y+z的值
x+y=8 y+z=12 x+z=10 x+y+z=
x+y=8 y+z=12 x+z=10 x+y+z=
{x+y-z=11 y+z-x=5 z+x-y=1
{x+y-z=11,x-y-z=-5,x-y+z=1
(x*x+2)(y*y+4)(z*z+8)=64xyz,求x,y,z
x+Y+Z=1 X+3Y+7Z=-1 X+5Y+8Z=2x+Y+Z=1X+3Y+7Z=-1X+5Y+8Z=2
{x+y+z=1 {x+3y+7z=-1 {x+5y+8z=2
{x+y+z=1 x-2y+3z=5 2x-3y-3z=-8
x+y+z=-1 4x-2y+3z=5 y-z=8-2x