若2x+3y-4z=7,x+2y-5z=2,则x+y+z的值为
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/25 15:54:39
若2x+3y-4z=7,x+2y-5z=2,则x+y+z的值为若2x+3y-4z=7,x+2y-5z=2,则x+y+z的值为若2x+3y-4z=7,x+2y-5z=2,则x+y+z的值为2x+3y-4
若2x+3y-4z=7,x+2y-5z=2,则x+y+z的值为
若2x+3y-4z=7,x+2y-5z=2,则x+y+z的值为
若2x+3y-4z=7,x+2y-5z=2,则x+y+z的值为
2x+3y-4z=7为一式
x+2y-5z=2为二式
一式减二式
得到x+y+z=5
x+y+z=5
1式减去2式即可
5
x+y+z=5
两个式子相减就可以了,答案是5
2x+3y-4z=7,x+2y-5z=2
所以2x+3y-4z=7,-x-2y+5z=-2
所以两式加起来
x+y+z=5
将2x+3y-4z=7减去x+2y-5z=2,得:x+y+z=5
若X:Y:Z=5:6:7那么(Y-X):(Y+Z)和(X+2Y+3Z):(3X+2Y+Z)
若x/2=y/3=z/4,则3x-2y+5z/x+y+z=
2x+5y+4z=6,3x+y-7z=-4,x+y-z=?
若4x=7y+5z,2x+y=z,则x:y:z的值为
X-Y-Z=0 X+Y-3Z=4 2X-5Y+7Z=21
3x+7y+4z=35,x+5y+2z=40,x+y+z=( )
{x+y+z=1 {x+3y+7z=2 {x+5y+19z=4
已知2x+5y+4z=6 3x+y-7z=-4求x+y-z
若x/3=y/4=z/5,求x+y+z/3x-2y+z的值.
5x+3y+2z=2011 4x+6y+7z=2012 求x+y+z
若xyz≠0且4(x/z)-5(y/z)=-2,(x/z)+4(y/z)=3,求x:y:z
1.{x:y:z=3:4:5 2x+3y-5z=-142.{x-y-z=-1 3x+5y+7z=11 4x-y+2z=-13.{x+y=1 x+z=0 2x+y+2z=44.{x-y+z=-3 2x-y-z=-2 -3x+y+z=-15.{x-y+z=-3 3x+y-4z=6 2x+y-z=36.{x-2y+5z=16 2x+y-5z=7 2x-y+z=38
(4x-2y-z)-{5x-[8y-2z-(x-2y)]-x-(3y-10z)}=?
x-y-z=-1 3x+5y+7z=11 4x-y+2z=-1 分别求出x=?y=?z=?
三元一次方程 X-y-z=-1 3x+5y+7z=11 4x-y+2z=-1 X=?Y=?Z=?
已知x+4y+3z=3x-2y-5z=0,求x+2y-z/2x-3y+7z的值
已知关于x y z的方程组2x-3y+5z=7 x+2y-3z=8,则4x+y-z=
若4x-3y-6z=0,x+2y-7z=0,则x+y+z/3x-y+z=?