已知an满足a1=三分之二 an+1=an-2/2an-3 求证1/an-1是等差数列如题
来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/27 18:55:41
已知an满足a1=三分之二an+1=an-2/2an-3求证1/an-1是等差数列如题已知an满足a1=三分之二an+1=an-2/2an-3求证1/an-1是等差数列如题已知an满足a1=三分之二a
已知an满足a1=三分之二 an+1=an-2/2an-3 求证1/an-1是等差数列如题
已知an满足a1=三分之二 an+1=an-2/2an-3 求证1/an-1是等差数列
如题
已知an满足a1=三分之二 an+1=an-2/2an-3 求证1/an-1是等差数列如题
证:
a(n+1)=(an -2)/(2an -3)
a(n+1) -1=(an-2-2an+3)/(2an-3)=(-an+1)/(2an-3)=-(an -1)/(2an-3)
1/[a(n+1) -1]=-(2an -3)/(an -1)=1/(an -1) -2
1/[a(n+1)-1]-1/(an -1)=-2,为定值.
1/(a1-1)=1/(2/3 -1)=-3
数列{1/(an -1)}是以-3为首项,-2为公差的等差数列.
题目看不明白,有图吗?
已知an满足a1=三分之二 an+1=an-2/2an-3 求证1/an-1是等差数列如题
已知数列{an}满足a(n+1)=an+n,a1=1,则an=
已知{an}满足a1=1,a(n+1)=2an+2,求an
已知数列{an}满足a(n+1)=an+lg2,a1=1,求an
已知数列{an}满足a1=1 an+1=an/(3an+1) 则球an
已知数列an满足a1=1,a(n+1)=an/(3an+2),则an=?
已知数列an满足条件a1=-2 a(n+1)=2an/(1-an) 则an=
已知数列{an}满足an+1=an+n,a1等于1,则an=?
已知数列{an}满足an+1=2an+3.5^n,a1=6.求an
已知{an}满足a1=1.an=3*n+2An-1,求an
已知数列{an}中满足(An+1-An)(An+1+An)=16,且a1=1,an
已知数列满足a1=1/2,an+1=2an/(an+1),求a1,a2已知数列满足a1=1/2,a(n+1)=2an/(an+1),求a1,a2;证明0
已知数列{an}满足a1=1,3a(n+1)+an-7
已知数列{an}满足a1=2,a(n+1)-an=a(n+1)*an,则a31=?
已知数列满足a1=2,a(n+1)=2an-1/an,证明1/an-1为等差
已知数列an满足a1=1,a(n+1)=an/(3an+1) 求数列通项公式
已知{an}满足a1=3,a(n+1)=2an+1求( an +1)是等比数列
已知数列{an}满足a(n+1)=an+3n+2,且a1=2,求an=?