1/2*4+1/4*6+1/6*8+····+1/2006*2008=几

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1/2*4+1/4*6+1/6*8+····+1/2006*2008=几1/2*4+1/4*6+1/6*8+····+1/2006*2008=几1/2*4+1/4*6+1/6*8+····+1/200

1/2*4+1/4*6+1/6*8+····+1/2006*2008=几
1/2*4+1/4*6+1/6*8+····+1/2006*2008=几

1/2*4+1/4*6+1/6*8+····+1/2006*2008=几
1/(2*4)=(1/2-1/4)*1/2
1/(4*6)=(1/4-1/6)*1/2
.
1/(2006*2008)=(1/2006-1/2008)
1/2*4+1/4*6+1/6*8+····+1/2006*2008
=1/2*(1/2-1/4+1/4-1/6+...+1/2006-1/2008)
=1/2*(1/2-1/2008)
=1/2*1003/2008
=1003/4016

1/(2*4)=(1/2-1/4)*1/2
1/(4*6)=(1/4-1/6)*1/2
......
1/(2006*2008)=(1/2006-1/2008)
1/2*4+1/4*6+1/6*8+····+1/2006*2008
=1/2*(1/2-1/4+1/4-1/6+...+1/2006-1/2008)
=1/2*(1/2-1/2008)
=1/2*1003/2008
=1003/4016

使用错项法~~
原式=1/2*(1/2-1/4+1/4-1/6+1/6-1/8....+1/2006-1/2008)=1/2*(1/2-1/2008)=1003/4016
因为分母是差2所以要提取1/2
若是1/3*7+1/7*11....这种就要提取1/4
要举一反三~~~
希望能对您有帮助!!!

1/n*(n+2)=(1/n - 1/n+2)/2 (右边通分一下就可以得到左边)
原式=(1/2)*(1/2-1/4+1/4-1/6+1/6……-1/2006+1/2006-1/2008)
=0.5*(1/2-1/2008)
=1003/4016

计算1/2×4+1/4×6+1/6×8+···+1/2006×2008 计算:(2+4+6+8+···+100)-(1+3+5+···+99) 1/(2*4)+1/(4*6)+1/(6*8)+········+1/(2006*2008)等于? 1/2*4+1/4*6+1/6*8+····+1/2006*2008=几 1/2*4+1/4*6+1/6*8+····+1/2006*2008=几 1/2*4+1/6*8+······+1/2006*2008+1/4*6+1/8*10+······+1/2004*2006=?*是乘号 /是分数线 1×2+2×3+3×4+4×5+5×6+6×7+7×8+8×9··········+100×101等于多少?1×2+2×3+3×4+4×5+5×6+6×7+7×8+8×9··········+n(n+1)这个要代数式. (2+4+6+8+······+100)—(1+3+5+7+······+99)等于几 (1+3+5++7+9······+2011)-(2+4+6+8······+2012)= 把1 9填入81格方框,不能重复· · 4 · · 5 · 6 ·9 · · 3 · · · 5 17 · · 6 · · · · 3· · 9 · 1 6 · 4 ·· 2 · 4 · · · 8 ·· 4 · 7 · · 5 · ·5 · · · · 7 · · 84 1 · · · 8 · · 5· 8 · 9 · · 6 · 4 1+2+3+4+5+6+7+8+9······+99=?1 俗语和名句的填空1······,自知之明.2······,行必果.3工欲善其事,······.4临渊羡鱼,······.5非学无以广才,······.6······,福兮祸之所伏.7项庄舞剑,······.8······,人以群 4/3×6/5×8/7×······×(2n+2)/(2n+1)求积 证明1·3·5·····(2n-1)/2·4·6·····2n 2011红领巾快乐数独答案一2·····4·9·631·4·8·8··97··3··3··2·95···95·86···15·3··7··9··47··5·7·3·182·3·4·····7二7·1·8·3·····413·6·2·6···4·8·8·5·1·2·61·····94·2·9·4·7·8· 计算 1/2*4+1/4*6+1/6*8+······+1/98*100的简便方法 2*4分之1加4*6分之1+6*8分之1······+48*50分之1=? 1/(2×4)+1/(4×6)+1/(6×8)+1/(8×10)+·····+1/(2008×2010)的算法(详细过程),