计算：x-2/4-2x-1/6＞1；x-10x+1/6≥2x+1/4-1.

计算:[(x^2 - 4)/(x^2 - x - 6) + (x+2)/(x-3)] / (x+1)/(x-3) 1.用公式计算：COSX=1-X*X/2!X*X*X*X/4!-X*X*X*X*X*X/6!.直到最后一项的绝对 计算1/x(x+2)+1/(x+2)(x+4)+1/(x+4)(x+6)+...1/(x+2004)(x+2006) 计算（x*x+4x+5）/（x+2）-（x*x+6x+10）/（x+3）+1 计算：（x+1)(x-2)(x-3)(x-6) 计算(x+1)(x+2)(x+3)(x+4) 如何计算 (x+1)(x+2)(x+3)(x+4) 计算(X-1)(X-2)(X-3)(X-4) (x-1)(x-2)(x-3)(x-4)-24计算 *-----------------------------------------------*| 6 4 X | 8 X X | X X 5 || X X X | X X X | X 7 8 || X X X | X X X | X X X ||---------------+---------------+--------------- || X X X | X X X | 5 1 X || X X X | X 6 X | X X X || 8 X X | 3 5 X | 2 X X || 计算:(4x^4-6x^2+2)(5x^3-2x^2+x-1), 计算：x(x^2+x-1)-(x^2-x+1) 计算5(x^2+x-3)-4x(6+x)+x(4-x)=02x(x-1)-x(2x-5) 计算：﹙﹣x﹚^4·x^3-x^7-2x^3·(-x)^4 计算：(2x-1)^2-2(x-2)(x+6) 计算 2+x+3/x-1*x^2-2x+1/x^2+6x+9 计算:x+2/x^2-2x-x-1/x^2-4x+4 分式计算：(x+2)/(x^2-2x)-(x-1)/(x^2-4x+4) 计算：1/X(X+2)+1/(X+2)(X+4)+...+1/(X+28)(X+30)