已知有理数A,B满足/A-2/+(3B+1)(3B+1)=0,求代数式-1/2A2-3AB-A/B

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已知有理数A,B满足/A-2/+(3B+1)(3B+1)=0,求代数式-1/2A2-3AB-A/B已知有理数A,B满足/A-2/+(3B+1)(3B+1)=0,求代数式-1/2A2-3AB-A/B已知

已知有理数A,B满足/A-2/+(3B+1)(3B+1)=0,求代数式-1/2A2-3AB-A/B
已知有理数A,B满足/A-2/+(3B+1)(3B+1)=0,求代数式-1/2A2-3AB-A/B

已知有理数A,B满足/A-2/+(3B+1)(3B+1)=0,求代数式-1/2A2-3AB-A/B
因为/A-2/与(3B+1)(3B+1)都是不小于0的数
而/A-2/+(3B+1)(3B+1)=0
所以A=2,B=-1/3
所以-1/2A2-3AB-A/B
=-2+2+6=6