解方程:2/(x+1)+3/(x-1)=6/(x^2-1)

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解方程:2/(x+1)+3/(x-1)=6/(x^2-1)解方程:2/(x+1)+3/(x-1)=6/(x^2-1)解方程:2/(x+1)+3/(x-1)=6/(x^2-1)2/(x+1)+3/(x-

解方程:2/(x+1)+3/(x-1)=6/(x^2-1)
解方程:2/(x+1)+3/(x-1)=6/(x^2-1)

解方程:2/(x+1)+3/(x-1)=6/(x^2-1)
2/(x+1)+3/(x-1)=6/(x^2-1)
乘以(x^2-1)=(x+1)(x-1)得
2(x-1)+3(x+1)=6
2x-2+3x+3=6
5x=6-1
5x=5
x=1
检验:x=1时,分母为0,即x=1是增根
所以原方程无解

2/(x+1)+3/(x-1)=3/(x-1)-3/(x+1),x=-1

两边同时乘(x+1)(x-1)
可得2(x-1)+3(x+1)=6
2x-2+3x+3=6
移项,可得:5x=5
x=1
我很辛苦的