(1)lg5+1g20= (2)lg200-1g2=
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(1)lg5+1g20=(2)lg200-1g2=(1)lg5+1g20=(2)lg200-1g2=(1)lg5+1g20=(2)lg200-1g2=(1)lg5+1g20=lg(5*20)=1g10
(1)lg5+1g20= (2)lg200-1g2=
(1)lg5+1g20= (2)lg200-1g2=
(1)lg5+1g20= (2)lg200-1g2=
(1)lg5+1g20=lg(5*20)=1g100=2
(2)lg200-1g2=lg(200/2)=lg100=2
(1)
lg5+1g20
=lg(5*20)
=lg100
=lg10²
=2lg10
=2
(2)
lg200-1g2
=lg(200/2)
=lg100
=lg10²
=2lg10
=2
肯定对
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(1)
lg5+1g20
=lg(5*20)
=lg100
=lg10²
=2lg10
=2
(2)
lg200-1g2
=lg(200/2)
=lg100
=lg10²
=2lg10
=2
肯定对
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有什么不明白可以继续问，随时在线等。
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(1)lg5+1g20
=lg（5×20）
=lg100
=lg10²
=2
(2)lg200-1g2
=lg（200÷2）
=lg100
=1g10²
=2
（lg2)^2+lg5·lg20-1=?
为什么lg5*lg20=lg5*(1+lg2)
2lg5+lg20=?lg5*lg20=?
lg5*lg20=?为什么lg5*lg20=lg5(1+lg2)=lg5+lg5lg2?明了明了
(lg2)^2 lg5×lg20－1
lg2+lg5=?1-lg2=?1-lg5=?2lg5+2/3lg8+lg5*lg20+(lg2)2=?
(lg5)²+lg5·lg20+1g4=?
(1)lg5+1g20= (2)lg200-1g2=
数学中为何lg5*lg20=(1-lg2)*(1+lg2)?
(1) lg5+lg20+(lg2)^2 (2)2^3+log2^5
log3 2+log3 1/2 +lg20 +lg5等于多少
lg4+lg5.lg20+(lg5)2
lg4+lg5.lg20+(lg5)2
对数lg2*lg5=?2lg（5）+2/3 lg8+lg5*lg20+lg2 =lg5^2+lg8^(2/3)+lg5*(lg4+lg5)+lg2 =lg100+lg5+2lg2*lg5+lg2 =2+(lg5+lg2) =2+1 =3 第二个等号lg5*(lg4+lg5)为什么=lg5+2lg2*lg5
log函数的简单计算(lg2)^2+lg5*lg20-1=_________ 求过程!
（lg2)*(lg2)+lg5*lg20-1怎么计算
(lg2)^2+lg5*lg20
(lg2)^2+lg20*lg5