已知1/x-1/y=-3,则x+3xy-y/3x-2xy-3y=

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已知1/x-1/y=-3,则x+3xy-y/3x-2xy-3y=已知1/x-1/y=-3,则x+3xy-y/3x-2xy-3y=已知1/x-1/y=-3,则x+3xy-y/3x-2xy-3y=1/x-

已知1/x-1/y=-3,则x+3xy-y/3x-2xy-3y=
已知1/x-1/y=-3,则x+3xy-y/3x-2xy-3y=

已知1/x-1/y=-3,则x+3xy-y/3x-2xy-3y=
1/x-1/y=-3 y-x+3xy=0 x=y+3xy
x+3xy-y/3x-2xy-3y=(x+3xy-y)/(3x-2xy-3y)=(6xy)/(7xy)=6/7

(x-3xy-y)/(3x-2xy-3y)
={xy[(1/y)-3-(1/x)]}/{xy[(3/y)-2-(3/x)]}
=[(1/y)-(1/x)-3]/[(3/y)-(3/x)-2]
=[(-3)-3]/[3*(-3)-2]
=(-6)/(-9-2)
=(-6)/(-11)
=6/11

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