min=x1log(x1)+x2log(x2)+x3*log(x3)；约束是x1+x2+x3=1; 为什么在lingo里报错.请大侠指导

来源：学生作业帮助网编辑：六六作业网时间：2024/11/15 05:57:37

min=x1*log(x1)+x2*log(x2)+x3*log(x3)；约束是x1+x2+x3=1;为什么在lingo里报错.请大侠指导min=x1*log(x1)+x2*log(x2)+x3*lo

min=x1*log(x1)+x2*log(x2)+x3*log(x3)；约束是x1+x2+x3=1; 为什么在lingo里报错.请大侠指导
min=x1*log(x1)+x2*log(x2)+x3*log(x3)；约束是x1+x2+x3=1; 为什么在lingo里报错.请大侠指导

min=x1*log(x1)+x2*log(x2)+x3*log(x3)；约束是x1+x2+x3=1; 为什么在lingo里报错.请大侠指导
min=x1*@log(x1)+x2*@log(x2)+x3*@log(x3);!函数前要加@,结束分号要用英文状态;
x1+x2+x3=1;