若(X+y-7)^2+│X^2-y^2-56│=0,则X-Y=?
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若(X+y-7)^2+│X^2-y^2-56│=0,则X-Y=?若(X+y-7)^2+│X^2-y^2-56│=0,则X-Y=?若(X+y-7)^2+│X^2-y^2-56│=0,则X-Y=?若(x+
若(X+y-7)^2+│X^2-y^2-56│=0,则X-Y=?
若(X+y-7)^2+│X^2-y^2-56│=0,则X-Y=?
若(X+y-7)^2+│X^2-y^2-56│=0,则X-Y=?
若(x+y-7)^2+│X^2-y^2-56│
所以x+y-7=0
x^2-y^2-56=0
所以x+y=7
x²-y²=56
则(x+y)(x-y)=56
所以x-y=56÷7=8
因为平方和绝对值有非负性，所以只能里面为0.所以可得x+y-7=0 x平方-y平方-56=0
然后得到x+y=7 x平方-y平方=56 平方差公式(x+y)(x-y)=56 再用这个除以x+y 等于8
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