化简:(x+y-z)^3n*(z-x-y)^2n*(x-z+y)^5n(n为正整数)

化简:(x+y-z)^3n*(z-x-y)^2n*(x-z+y)^5n(n为正整数) 化简-(-3x-y+2z)-{-x+【4x-(x-y-z)-3x+2z} 化简(y-x)(z-x)/(x-2y+z)(x+y-2z)+（z-y)(x-y)/(x-2z+y)(y+z-2x)+(x-z)(y-z)/(y+z-2x)(x-2y+z) 化简(y-x)(z-x)/(x-2y+z)(x+y-2z)+（z-y)(x-y)/(xy-2z)(y+z-2x)+(x-z)(y-z)/(y+z-2x)(x-2y+z)速速回答 化简(x+Y)^2(y+z-x)(z+x-y)+(x-y)^2(x+y+z)(x+y-z) 化简:(2x-y-z)/(x-y)(x-z)+(2y-z-x)/(y-z)(y-x)+(2z-x-y)/(z-x)(z-y)化简:(2x-y-z)/(x-y)(x-z)+(2y-z-x)/(y-z)(y-x)+(2z-x-y)/(z-x)(z-y)我知道把分母化成一样的、但是之后怎么算? x+=y+=z; printf(%d ,z+=x>y?x++:y++);过程是怎么的?int x=1,y=2,z=3;x+=y+=z;printf(%d ,z+=x>y?x++:y++);x=y=z=-1;(++x||(++y&&++z));printf(%d %d %d ,x,y,z); 化简(y-z)^2/(x-y)(x-z)+(z-x)^2/(y-x)(y-z)+(x-y)^2/(z-x)(z-y) 试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y) 已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z x-y/(z-x)(z-y) 一y-z/(x-y)(x-z) ＋z-x/(y-z)(y-x) x^-(y-z)^/(x+y)^-z^ 计算（x+y-z)(x-y-z) 计算：(x-y+z)(-x+y+z) (x+y-z)(x-y+z)= 2(x+y)(x+y-z)+3(y-z)(x+y-z) 请问以下这条n阶行列式怎么解?Dn=| x y y y ...y|| z x y y.y|| z z x y .y|| z ...x y| | z z z ......x| x y y ...y z x y ...y z z x ...y ........z z z ...x 求解行列式.