解方程组:x/2=y/3=z/5 x-2y+3z=22

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解方程组:x/2=y/3=z/5x-2y+3z=22解方程组:x/2=y/3=z/5x-2y+3z=22解方程组:x/2=y/3=z/5x-2y+3z=22因为x/2=y/3y/3=z/5即x=2y/

解方程组:x/2=y/3=z/5 x-2y+3z=22
解方程组:x/2=y/3=z/5 x-2y+3z=22

解方程组:x/2=y/3=z/5 x-2y+3z=22
因为x/2=y/3 y/3=z/5
即x=2y/3 z=5y/3
所以x-2y+3z=22等价为2y/3-2y+3*5y/3=22,因此y=6,x=4 z=10

x=2/3y;z=5/3y;带入第二个方程有2/3y-2y+5y=22。解得y=6.带入第一个方程解得x=4,z=10