sat which of the following compounds is isoelectronic with co(carbon monooxyde) a.H2b.Cl2c.N2d.CO2e.NO2为什么?given the hypothetical reaction 2A+B=C+3D ,the equilibrium constant for this reaction is I.directly proportional to the concentration of

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satwhichofthefollowingcompoundsisisoelectronicwithco(carbonmonooxyde)a.H2b.Cl2c.N2d.CO2e.NO2为什么?give

sat which of the following compounds is isoelectronic with co(carbon monooxyde) a.H2b.Cl2c.N2d.CO2e.NO2为什么?given the hypothetical reaction 2A+B=C+3D ,the equilibrium constant for this reaction is I.directly proportional to the concentration of
sat
which of the following compounds is isoelectronic with co(carbon monooxyde)
a.H2
b.Cl2
c.N2
d.CO2
e.NO2
为什么?
given the hypothetical reaction 2A+B=C+3D ,the equilibrium constant for this reaction is
I.directly proportional to the concentration of D cubed.
II,inversely proportional to the concentration of A.
III.inversely proportional to the concentration of C.
I
不是平衡常数只受温度影响么?为什么?
第二题 为什么II不对啊?

sat which of the following compounds is isoelectronic with co(carbon monooxyde) a.H2b.Cl2c.N2d.CO2e.NO2为什么?given the hypothetical reaction 2A+B=C+3D ,the equilibrium constant for this reaction is I.directly proportional to the concentration of
(1)which of the following compounds is isoelectronic with co(carbon monooxyde)
题目的意思是以下的化合物有哪种是和CO(一氧化碳)等电子的?
C的电子数是6,质子数6,中子数6.相对原子质量为中子+质子=12.核外电子排布为 2:4
O的电子数是8,质子数8,中子数8.相对原子质量为中子+质子=16.核外电子排布为 2:6
所以CO的电子数是6+8=14
5个选项的电子数分别为
a,H2=2 b,Cl2=34 c,N2=14 d,CO2=22 e.NO2=23
所以答案选C
(2) given the hypothetical reaction 2A+B=C+3D ,the equilibrium constant for this reaction is
给出假设的反应方程2A+B=C+3D ,对反应的平衡常数,下列说法正确的是:
这个反应中的产物和原料的浓度都是影响反应的平衡常数的(当然在液相和气象反应中的固态物体是不影响的)题目中没有明确说明的情况下,视为全部为非固体:
具体的方程为 K=C*D^3/A^2*B
答案中 1说的是反应常数与D含量的3次方成正比.
11说的是反应常数与A含量成反比
111说的是反应常数与C含量成反比
根据平衡常数方程可以得出1是正确答案.

楼上显然错了..CO电子数怎么可能是28??6+8=14....
compounds is isoelectronic with co(carbon monooxyde)
意思是那个化合物是和CO等电子..
CO电子数是14
显然只有N2,也是14
H2是2 CL2是34,CO2是22,NO2是23
这道题楼上又错了..K=C*D^3/A^2*B ...

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楼上显然错了..CO电子数怎么可能是28??6+8=14....
compounds is isoelectronic with co(carbon monooxyde)
意思是那个化合物是和CO等电子..
CO电子数是14
显然只有N2,也是14
H2是2 CL2是34,CO2是22,NO2是23
这道题楼上又错了..K=C*D^3/A^2*B 应该是反应物/生成物
还有,这道题不严谨..要说明ABCD都是气体才行。
这里是让你求平衡常数..
如果你已知D的立方的浓度的话,平衡常数自然正比于它...而不是问你平衡常数和什么有关。即使温度变了,平衡常数变了,那么相应的D的浓度也会改变。

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电子数相等

CO一共有12+16=28个electrons,并且他们是covalent bond,只有N2也是这样的,28个electrons并且是covalent bond
equilibrium constant是[A]^2[B]/[C][D]^3,虽然我认为instead of directly proportional, it should be inversely proportional, but obviously the other 2 answers are wrong

楼主你好!
第一题
所有原子的价电子数目加起来相等的两个分子、离子或者原子就是等电子体。
CO有 6 + 8 == 14 个电子。五个选项中只有 N2 有 7 + 7 == 14 个电子,故选 C。
第二题
Ka == ([C] * [D]^3) / ([A]^2 * [B])
由这个公式可以知道只有 I 是对的。
平衡常数是化学反应的特性...

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楼主你好!
第一题
所有原子的价电子数目加起来相等的两个分子、离子或者原子就是等电子体。
CO有 6 + 8 == 14 个电子。五个选项中只有 N2 有 7 + 7 == 14 个电子,故选 C。
第二题
Ka == ([C] * [D]^3) / ([A]^2 * [B])
由这个公式可以知道只有 I 是对的。
平衡常数是化学反应的特性常数,它只和温度有关,例如 Hydrogen Sulfide 在 298K 的时候的化学平衡常数就是 Ka == 5.7 * 10^(-8) 。注意这个 Ka 是在 298K 下的。
如果温度一定,那么这个化学反应在化学平衡的时候尽管ABCD的浓度会不一样,但是 Ka 是定值。
Ka 也是反应进行程度的标志,反映出反应的完全程度。反应物的K值越大,说明 product 浓度越大,reactant 浓度越小,product 转化率越大,forward reaction 趋势越强。

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