main ( ) {int y ,f ; scanf ( "% d ",&y ) ; if ( y % 400 = = 0 ) f = 1; else if ([1]) f = 1 ; else以下程序的功能是判断输入的年份是不是闰年,请在[ ]内添入正确的内容.main ( ){int y ,f ;scanf ( "% d ",&y ) ;if ( y % 400 = = 0

#include using namespace std; int main() { int a,b,c; a=3; int f(int x,int y,int z);#include using namespace std; int main() {int a,b,c;a=3;int f(int x,int y,int z); cin>>a>>b>>c;c=f(a,b,c);cout #include void f(int*x,int y) {*x=y+1;y=*x+2;} main() {int a=2,b=2; f(&a,b); printf(%d %d#includevoid f(int*x,int y){*x=y+1;y=*x+2;}main(){int a=2,b=2;f(&a,b);printf(%d %d,a,b);} 我想搞个X的Y次方的 算法 #include stdafx.hint main(int argc,char* argv[]){int pow(int x,int y);int a,b,c;scanf(%f,%f,&a,&b);c=pow(a,b);printf(%f ,c);return 0;}int pow(int x,int y){int i,z;i=1;z=x;while(i C语言 答案为什么是8 4 #includevoid f(int y,int *x){y=y+*x;*x=*x+y;}main(){int x=2,y=4;f(y,&x);printf(%d %d ,x,y);} #includevoid f(int y,int *x){ y=y+*x; *x=*x+y;} void main(){ int x=2,y=4;f(y,&x);printf(%d,%d ,x,y);} void f( int y,int *x) {y=y+*x; *x=*x+y;} main( ) { int x=2,y=4; f(y,&x); printf(%d %d ,x,y); } void f( int y,int *x){y=y+*x; *x=*x+y;}main( ){ int x=2,y=4;f(y,&x);printf(%d %d ,x,y);} 执行后输出的结果是 . 有三个数字abc依次按大小顺序 C#includeint main(){int max(int x,int y,int z);int med(int x,int y,int z);int min(int x,int y,int z);int a,b,c,d,e,f;scanf(%d,%d,%d,&a,&b,&c);d=max(a,b,c);e=med(a,b,c);f=min(a,b,c);printf(%d,%d,%d,d,e,f);re #includestdio.h #define F(y) 3.84+y #define PR(a) printf(%d,(int)(a)) main(){ int x=3; PR(F(3)*#includestdio.h#define F(y) 3.84+y#define PR(a) printf(%d,(int)(a))main(){int x=3;PR(F(3)*x); }为什么结果是12啊? int main() { float a=1.0f; cout C++中关于求两个数的最大公约数与最小公倍数#includeusing namespace std;int f(int a,int b);int g(int c,int d);void main(){ int x,y,m,n;couty;m=f(a,b);n=g(c,d);cout main ( ) {int y ,f ; scanf ( % d ,&y ) ; if ( y % 400 = = 0 ) f = 1; else if ([1]) f = 1 ; else以下程序的功能是判断输入的年份是不是闰年,请在[ ]内添入正确的内容.main ( ){int y ,f ;scanf ( % d ,&y ) ;if ( y % 400 = = 0 求十个数中的最大值和最小值main(){int a[2],b[10],i;void f(int x[],int y[]);for(i=0;i请问为什么得出的结果不正确 C语言 请帮忙详细解释下x++和++x#include int x = 1;int f(int x){ return (x++);}main(){ int y; y = f(2); x = f(x); printf(y=%d x=%d ,y,x);}运行结果是2,1有点搞不懂return（x++）到底是要返回什么值啊? #define F(x,y)x*(y) void main() {int a=3,b=4,c; c=F(a+b,(a++)+(b++));#define F(x,y)x*(y) void main() {int a=3,b=4,c; c=F(a+b,(a++)+(b++)); printf(%d/n,c);} 答案是31,求详解. 1)int z=5;f ( ){ static int x=2; int y=5;x=x+2; z=z+5;y=y+z;printf (〃%5d%5d 〃,x,z);}main ( ){ static int x=10; int y;y=z;printf (〃%5d%5d 〃,x,z);f ( );printf (〃%5d%5d 〃,x,z);f ( );}2)struct prob { char *a;int b;} x[ ]={ 〃Zhang San〃, main(){int n=6,x;x=f(n);printf(%d!=%d ,n,x);}f(int n){int y'if(n==1)y=1;else y=n*f(n-1)main(){int n=6,x;x=f(n);printf(%d!=%d ,n,x);}f(int n){int y'if(n==1) y=1;else y=n*f(n-1);return()}求详解 ——————————————— 特 #include void main() { int a,b; float x,y; char c1,c2; scanf(a=%d b=%d,&a,&b); scanf(%f#includevoid main(){int a,b;float x,y;char c1,c2;scanf(a=%d b=%d,&a,&b);scanf(%f%e,&x,&y);scanf(%c%c,&c1,&c2);printf(%d%d%f%f%c%c);}老运行不正常 请 void f( int y,int *x) {y=y+*x; *x=*x+y;} main( ) { int x=2,y=4; f(y,&x); printf(%d %d ,x,y); }为什么输出结果是8,4 .即为什么x取了返回值 而y没有