sin(П/4-3x)cos(П/3-3x)-cos(П/6+3П)-sin(П/4+3П)

来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/19 04:49:36
sin(П/4-3x)cos(П/3-3x)-cos(П/6+3П)-sin(П/4+3П)sin(П/4-3x)cos(П/3-3x)-cos(П/6+3П)-sin(П/4+3П)sin(П/4-

sin(П/4-3x)cos(П/3-3x)-cos(П/6+3П)-sin(П/4+3П)
sin(П/4-3x)cos(П/3-3x)-cos(П/6+3П)-sin(П/4+3П)

sin(П/4-3x)cos(П/3-3x)-cos(П/6+3П)-sin(П/4+3П)
sin(П/4-3x)cos(П/3-3x)-cos(П/6+3x)sin(П/4+3x)
=cos[П/2-(П/4-3x)]sin[П/2-(П/3-3x)]-cos(П/6+3x)sin(П/4+3x)
=cos(П/4+3x)sin(П/6+3x)-cos(П/6+3x)sin(П/4+3x)
=-2sinП/24cos(5П/24+3x)

sin(П/4-3x)cos(П/3-3x)-cos(П/6+3П)-sin(П/4+3П) 化简[1-(sin^4x-sin^2cos^2x+cos^4x)/(sin^2)]+3sin^2x 证明sin^2(x)+cos^2(x+30)+sin(x)cos(x+30)=3/4 化简2sin^2[(π/4)+x]+根号3(sin^x-cos^x)-1 2(sin^6x+cos^6)-3(sin^4x+cos^4x) 怎样判断被积函数R(sin x,cos x)是关于sin x 的奇函数?RT,例(sin x cos^3 x)/(1+sin^4 x)是关于cos x 的奇函数,为什么? sin(5x)-sin(3x)= 根号2cos(4x)1.sin(5x)-sin(3x)= (根号2)cos(4x)解方程2.sin(x)+sin(2x)+sin(3x)=1+cos(x)+cos(2x) 化简sin(x+7π/4)+cos(x-3π/4)步骤我已经找到撒sin(x+7π/4)+cos(x-3π/4)=sin(x+2π-π/4)+cos(x-π+π/4)我问下这一步是在干嘛?=sin(x-π/4)+cos[-(π-x-π/4)]=sin(x-π/4)+cos(π-x-π/4)=sin(x-π/4)-cos(x+π/4)=sin(x-π/4)-cos(x+π/2- (1-(sin^4x-sin^2xcos^2x+cos^4x)/sin^2x +3sin^2x 化简[1-(sin^4 x-sin^2 xcos^2 x+cos^4 x)]/(sin^2 x)+3sin^2 x 化简sin(x)(cos(x)+cos(3x)+cos(5x)+cos(7x)) 化简(1)√3sin x+cos x (2)√2(sin x-cos x) (3)√2cos x-√6sin x 已知sin(x)+3cos(x)=2,求sin(x)-cos(x)/sin(x)+cos(x)=? tan²α-sin²α=tan²α×sin²α(cosα-1)²+sin²α=2-2cosαsin四次方x+cos四次方x=1-2sin³xcos²x已知tanα-3求:①4sinα-2cosα/5cosα+3tanα②sinαcosα③(sinα+cosα)²已知cosα=1/4求sinα sin[cos^2(x^3+x)],求导 根号3sin x+cos x要化简 sin cos之间怎么转换?sin(π/3-2X)等于cos多少? 关于sin^2x+cos^2x 的应用式子:cos^6x+sin^6x=(cos^2x+sin^2x)(cos^4x-cos^2xsin^x+sin^4x)=(cos^2x+sin^2x)^2-3sin^2xcos^2x 求这两步算法中的具体思路 ps:cos^2x=cosx的二次方