sin(2x+∏/6)-cos(2x+∏/3)最小正周期和最大值是多少?

化简(sin^2x-cos^4x+cos^2x-sin^4x)/(sin^2x-cos^6x+cos^2x-sin^6x) 2(sin^6x+cos^6)-3(sin^4x+cos^4x) 已知tan=2,求(cos x+sin x)/(cos x-sin x)+sin^2x 化简(sin x+cos x-1)(sin x-cos x+1)/sin 2x sin(2x+∏/6)-cos(2x+∏/3)最小正周期和最大值是多少? 化简√2sin(∏/4-X)+√6cos(∏/4-x) 证明一个sin&cos的等式证明 1+sin^2(x)+sin^4(x)+sin^6(x)=[1-sin^8(x)]/[cos^2(x)] 2cos x (sin x -cos x)+1 y=2cos x (sin x+cos x) 化简sin(x)cos(x)cos(2x) 化简sin(x)cos(x)cos(2x) sin x cos x cos 2x 化简 化简（1)√3sin x+cos x (2）√2(sin x-cos x) （3）√2cos x-√6sin x (sin^2x+cos^2x )(sin^2x-cos^2x)怎么得sin^2x-cos^2x? 已知sin(x)+3cos(x)=2,求sin(x)-cos(x)/sin(x)+cos(x)=? 化简 cos^2(x)*sin^2(x)-sin^2(x) 化简 cos^(2)(x)*sin^(2)(x)-sin^(2)(x) 化简sin^4x-sin^2x+cos^2x