sin^4x cos^2x+cos^4x sin^2 x=sin^2x*cot^2x 怎么得来sin^4x cos^2x+cos^4x sin^2 x=sin^2x*cot^2x 怎么得来
来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/25 09:36:11
sin^4xcos^2x+cos^4xsin^2x=sin^2x*cot^2x怎么得来sin^4xcos^2x+cos^4xsin^2x=sin^2x*cot^2x怎么得来sin^4xcos^2x+c
sin^4x cos^2x+cos^4x sin^2 x=sin^2x*cot^2x 怎么得来sin^4x cos^2x+cos^4x sin^2 x=sin^2x*cot^2x 怎么得来
sin^4x cos^2x+cos^4x sin^2 x=sin^2x*cot^2x 怎么得来
sin^4x cos^2x+cos^4x sin^2 x=sin^2x*cot^2x 怎么得来
sin^4x cos^2x+cos^4x sin^2 x=sin^2x*cot^2x 怎么得来sin^4x cos^2x+cos^4x sin^2 x=sin^2x*cot^2x 怎么得来
原式等于 sin^2(sin^2+cos^2)+cos^2 = sin^2*(1)+cos^2 = sin^2+cos^2 = 1
这个不是等于1吗
应该=sin²xcos²x吧!
sin^4x cos^2x+cos^4x sin^2 x
原式=sin²x*sin²xcos²x+cos²x*sin²xcos²x
=sin²xcos²x(sin²x+cos²x)
...
全部展开
应该=sin²xcos²x吧!
sin^4x cos^2x+cos^4x sin^2 x
原式=sin²x*sin²xcos²x+cos²x*sin²xcos²x
=sin²xcos²x(sin²x+cos²x)
=sin²xcos²x
【中学生数理化】团队wdxf4444为您解答!祝您学习进步
不明白可以追问!
满意请点击下面的【选为满意回答】按钮,O(∩_∩)O谢谢
收起
化简sin^4x+cos^2x
化简(sin^2x-cos^4x+cos^2x-sin^4x)/(sin^2x-cos^6x+cos^2x-sin^6x)
化简sin^4x-sin^2x+cos^2x
化简:sin^4 x-sin^2 x+cos^2 x
证明sin^4x-cos^4x=sin^2x-cos^2x
求证sin^4x-cos^4x=sin^2x-cos^2x
证明sin^2(x)+cos^2(x+30)+sin(x)cos(x+30)=3/4
用cos x表示sin^4 x -sin^2 x +cos^2 x
用cos x表示sin^4x-sin^2 x+cos^2 x
求证(cos^2 x-sin^2 x)(cos^4 x+sin^4 x)+1/4 sin 2x sin 4x=cos 2x
2(sin^6x+cos^6)-3(sin^4x+cos^4x)
化简[1-(sin^4x-sin^2cos^2x+cos^4x)/(sin^2)]+3sin^2x
化简cos^4x+sin^4x
化简:cos^4(X)-sin^4(X)
关于三角函数的一道题(高中)cos(10)*cos(20)*cos(40)=?类似cos(X)*cos(2x)*cos(4x)=?sin(x)*sin(2x)*sin(4x)=?的题目有没有什么规律
求函数y=7-4sin(x)cos(x)+4cos^2(x)-4cos^4(x)值
cos 2x(1-2sin^2 2x) + cos 4x (1+cos 2x)=
关于sin^2x+cos^2x 的应用式子:cos^6x+sin^6x=(cos^2x+sin^2x)(cos^4x-cos^2xsin^x+sin^4x)=(cos^2x+sin^2x)^2-3sin^2xcos^2x 求这两步算法中的具体思路 ps:cos^2x=cosx的二次方