tanα=3^α tanβ =3^(-α )且α -β =π/6 则α 等于

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tanα=3^αtanβ=3^(-α)且α-β=π/6则α等于tanα=3^αtanβ=3^(-α)且α-β=π/6则α等于tanα=3^αtanβ=3^(-α)且α-β=π/6则α等于tan(A-B

tanα=3^α tanβ =3^(-α )且α -β =π/6 则α 等于
tanα=3^α tanβ =3^(-α )且α -β =π/6 则α 等于

tanα=3^α tanβ =3^(-α )且α -β =π/6 则α 等于
tan(A-B)=(tanA-tanB)/(1+tanAtanB)=√3/3
3^α-3^(-α )/(1+3^α*3^(-α ))=√3/3
3^α-3^(-α )/2=√3/3
令x=3^α x-1/x)=2√3/3
x^2-2√3/3*x-1=0
x=√3 ∴a=1/2

证明:tanα+tanβ=tan(α+β)-tanαtanβtan(α+β) tanα+tanβ+根号3tanα*tanβ=根号3 求 tan(α+β)=? 已知α+β=60°且tanα,tanβ都存在tanα+tanβ+根号3tanαtanβ=? 已知β-a=γ-β=π/3,求tanαtanβ+tanβtanγ+tanγtanα的值 2tanα／(1-tanαtanα)=-4／3求tanα 2tanα／(1-tanαtanα)=-4／3求tanα要过程知tanα=3tanβ,且0 知tanα=3tanβ,且0 α+β=2π/3,√3tanα+√3tanβ-3tanαtanβ= 已知tanα+tanβ=-5/3,tanα×tanβ=-7/3,求cos（α+β）已知锐角α,β满足3tanα=tan(α+β)则tanβ最大值若tanα=3,tanβ=2/3,则tan(α+β) = 若tanα=3,tanβ=4/3则tan(α-β)=? 若tanα=3,tanβ=4/3则tan(α+β)=? tanα=-1/3,tanβ=-1/7,则tan(2α+β)= tan(α+β)=2,tanβ=-3,则tanα= tanα=1/2,tanβ=3,求tan(2α-β)的值 tanα=1/7,tanβ=1/3,tan(α+2β)