已知x/y+z=a,y/x+z=b.z/x+y=c且abc不等于0求a+1分之a+b+1分之b+c+1分之c 等于多少
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已知x/y+z=a,y/x+z=b.z/x+y=c且abc不等于0求a+1分之a+b+1分之b+c+1分之c等于多少已知x/y+z=a,y/x+z=b.z/x+y=c且abc不等于0求a+1分之a+b
已知x/y+z=a,y/x+z=b.z/x+y=c且abc不等于0求a+1分之a+b+1分之b+c+1分之c 等于多少
已知x/y+z=a,y/x+z=b.z/x+y=c且abc不等于0求a+1分之a+b+1分之b+c+1分之c 等于多少
已知x/y+z=a,y/x+z=b.z/x+y=c且abc不等于0求a+1分之a+b+1分之b+c+1分之c 等于多少
这种东西叫轮换式.它的意思是x换成y,y换成z,z换成x时,值不变.
求a/(a+1)+a/(b+1)+c/(c+1)
怎么求它呢?
a/a+1=1- 1/(a+1)
b/b+1=1-1/(b+1)
c/c+1=1-1/(c+1)
a/(a+1)+a/(b+1)+c/(c+1)=3-1/(1+a)-1/(1+b)-1/(1+c)①
1+a=1+x/y+z=(x+y+z)/(y+z)
1/(1+a)=(y+z)/(x+y+z)
①变为3-(y+z)/(x+y+z)-(y+x)/(x+y+z)-(x+z)/(x+y+z)
=3-2(x+y+z)/(x+y+z)
=1
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