若x^2-2x+y^2+6y+10=0
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若x^2-2x+y^2+6y+10=0若x^2-2x+y^2+6y+10=0若x^2-2x+y^2+6y+10=0可以把10分成1+9就变成(X平方-2X+1)+(Y平方+6Y+9)=0就是平方差公式
若x^2-2x+y^2+6y+10=0
若x^2-2x+y^2+6y+10=0
若x^2-2x+y^2+6y+10=0
可以把10分成1+9就变成(X平方-2X+1)+(Y平方+6Y+9)=0就是平方差公式
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已知x^2+y^2+6x-2y+10=0,求x+y/x-y的值谢谢