若x^2+y^2+2x-6y=10=0,则x-y=
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若x^2+y^2+2x-6y=10=0,则x-y=若x^2+y^2+2x-6y=10=0,则x-y=若x^2+y^2+2x-6y=10=0,则x-y=(x+1)^2+(y-3)^2=0x=-1y=3x
若x^2+y^2+2x-6y=10=0,则x-y=
若x^2+y^2+2x-6y=10=0,则x-y=
若x^2+y^2+2x-6y=10=0,则x-y=
(x+1)^2+(y-3)^2=0
x=-1 y=3 x-y=-4
谢了
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