已知(3a-b)/(2b-a)=7,(x+y)/(2x-y)=5,求(3ax-by)/(ax+2by)3a-b=7(2b-a),a=3/2b,x+y=5(2x-y),x=2/3y∴ax-2by/ax+2by=by-2by/by+2by……帮我找找哪错了,接下来该怎么写

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已知(3a-b)/(2b-a)=7,(x+y)/(2x-y)=5,求(3ax-by)/(ax+2by)3a-b=7(2b-a),a=3/2b,x+y=5(2x-y),x=2/3y∴ax-2by/ax+

已知(3a-b)/(2b-a)=7,(x+y)/(2x-y)=5,求(3ax-by)/(ax+2by)3a-b=7(2b-a),a=3/2b,x+y=5(2x-y),x=2/3y∴ax-2by/ax+2by=by-2by/by+2by……帮我找找哪错了,接下来该怎么写
已知(3a-b)/(2b-a)=7,(x+y)/(2x-y)=5,求(3ax-by)/(ax+2by)
3a-b=7(2b-a),a=3/2b,x+y=5(2x-y),x=2/3y
∴ax-2by/ax+2by=by-2by/by+2by……
帮我找找哪错了,接下来该怎么写

已知(3a-b)/(2b-a)=7,(x+y)/(2x-y)=5,求(3ax-by)/(ax+2by)3a-b=7(2b-a),a=3/2b,x+y=5(2x-y),x=2/3y∴ax-2by/ax+2by=by-2by/by+2by……帮我找找哪错了,接下来该怎么写
其实你已经基本做出来了,就差一点了,得到(by-2by)/(by+2by)=-by/3by=-1/3,把by当成一个整体就行

∴ax-2by/ax+2by=by-2by/by+2by……
应该是3ax-2by/ax+2by=3by-2by/by+2by=1/3

3a-b=7(2b-a),所以a=3/2b,x+y=5(2x-y),所以x=2/3y
∴(3ax-by)/(ax+2by)=(3*3/2b*2/3y
-by)/(3/2b*2/3y+2by)=2by/3by=2/3