若两圆x^2+y^2-10x-10y=0与x^2+y^2-6x+2y-40=0相交于两点,则它们的公共弦所在的直线方程是
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若两圆x^2+y^2-10x-10y=0与x^2+y^2-6x+2y-40=0相交于两点,则它们的公共弦所在的直线方程是若两圆x^2+y^2-10x-10y=0与x^2+y^2-6x+2y-40=0相
若两圆x^2+y^2-10x-10y=0与x^2+y^2-6x+2y-40=0相交于两点,则它们的公共弦所在的直线方程是
若两圆x^2+y^2-10x-10y=0与x^2+y^2-6x+2y-40=0相交于两点,则它们的公共弦所在的直线方程是
若两圆x^2+y^2-10x-10y=0与x^2+y^2-6x+2y-40=0相交于两点,则它们的公共弦所在的直线方程是
两个式子相减即可
x+3y-10=0
{4x-3y-10=0 3x-2y=0,{3x-4(x-y)=2 2x-3y=1,{2(x+y)-(x-y)=3 (x+y)-2(x-y)=1
若x-y不等于0,2x-3y=0,则分式(10x-11y)/(x-y)的值是()?(10x-11y)/(x-y) =[(8x-8y)+(2x-3y)]/(x-y) =8为什么8X-8Y=8?(10x-11y)/(x-y)=[(8x-8y)+(2x-3y)]/(x-y)=8+(2x-3y)]/(x-y)=8+0=8
x,y 满足x(x-2)-y(y-6)=-10,求x,y的值
x-y/x-x+y/y-(x+y)(x-y)/y² y/x=2
x^2+4y^2-6x+4y+10=0,求x^4-y^4/(x+2y)(x-2y)*x+2y/xy^2+y^3除以(x^2+y^2/y)^2的值
(x+y)^2/y^2-xy÷[-y^2+xy/(x-y)^2,x=0,y=根号10
2x-y=0与x+y=10
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已知:4x^2+y^2-4x-6y+10=0,求y/x-x/y的值
已知x、y满足:x^2+y^2+6x-10y+34=0,求y-x的值
若x^2+y^2-10x-6y+34=0,求(x-y)/(x+y)的值
已知(x+y)(x+y-10)+25=0,且x-y=2,求x,y的值?
已知实数x, y满足x²+y²-2x+6y+10=0,求y∧-x.