化简:2√(9x)/3+6√(x/4)-2x√(1/x)
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化简:2√(9x)/3+6√(x/4)-2x√(1/x)化简:2√(9x)/3+6√(x/4)-2x√(1/x)化简:2√(9x)/3+6√(x/4)-2x√(1/x)2√(9x)/3+6√(x/4)
化简:2√(9x)/3+6√(x/4)-2x√(1/x)
化简:2√(9x)/3+6√(x/4)-2x√(1/x)
化简:2√(9x)/3+6√(x/4)-2x√(1/x)
2√(9x)/3+6√(x/4)-2x√(1/x)
=2√(3^2x)/3+6√(x/2^2)-2x√(x/x^2)
=(2*3/3)√x+(6/2)√x-2(x/x)√x
=2√x+3√x-2√x
=3√x
=3√x
=3√x
2√(9x)/3+6√(x/4)-2x√(1/x)
=2*3√x/3+6√x*1/2-2√(x^2*1/x)
=2√x+3√x-2√x
=3√x
化简:[√(x^2-6x+9)/x^2-x-12]*(x^3-16x)/(x^2-3x)-1/(x+3) {x>3}
xy²/(x²y-y) × x²/(x²+x)=(x²-3x)/(x²-5x) × 2x-10/(x²-6x+9)=化简求植x²-1/(x²-x-2)除以x/2x-4,其中x=1/2[x-x/(x+1)]除以[x/(2x-4)] ,其中x=√2+1
化简:2√(9x)/3+6√(x/4)-2x√(1/x)
化简:2√(9x)/3+6√(x/4)-2x√(1/x)
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xy²/(x²y) - y×x²/(x²+x)=(x²-3x)/(x²-5x×2x) - 10/(x²-6x+9)=2a/(a²-4) - 1/(a-2)=2/(1-a ) - 1/(a-1)=x²-1/(x²-x-2)除以x/2x-4,其中x=1/2[x-x/(x+1)]除以[x/(2x-4)] ,其中x=√2+1
帮个忙 求你们了 急用xy²/(x²y-y) × x²/(x²+x)=(x²-3x)/(x²-5x) × 2x-10/(x²-6x+9)=化简求植x²-1/(x²-x-2)除以x/2x-4,其中x=1/2[x-x/(x+1)]除以[x/(2x-4)] ,其中x=√2+1
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2√(9x)/3+6√(x/4)-2x√(1/x)