集合A={(x,y)|x^2+mx-y+2=0},集合B={(x,y)|x-y+1=0,且0
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集合A={(x,y)|x^2+mx-y+2=0},集合B={(x,y)|x-y+1=0,且0集合A={(x,y)|x^2+mx-y+2=0},集合B={(x,y)|x-y+1=0,且0集合A={(x,
集合A={(x,y)|x^2+mx-y+2=0},集合B={(x,y)|x-y+1=0,且0
集合A={(x,y)|x^2+mx-y+2=0},集合B={(x,y)|x-y+1=0,且0
集合A={(x,y)|x^2+mx-y+2=0},集合B={(x,y)|x-y+1=0,且0
很简单,我初二的都会.
A交B不等于空集,则方程组x^2+mx-y+2=0 ①,x-y+1=0 ② 有实数解,且0
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集合A={(x,y)|x^2+mx-y+2=0},集合B={(x,y)|x-y+1=0,且0
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