已知sin(a+π/6)=1/3,则cos(2a-2π/3)的值是

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已知sin(a+π/6)=1/3,则cos(2a-2π/3)的值是已知sin(a+π/6)=1/3,则cos(2a-2π/3)的值是已知sin(a+π/6)=1/3,则cos(2a-2π/3)的值是s

已知sin(a+π/6)=1/3,则cos(2a-2π/3)的值是
已知sin(a+π/6)=1/3,则cos(2a-2π/3)的值是

已知sin(a+π/6)=1/3,则cos(2a-2π/3)的值是
sin(a+π/6)=cos(π/3-a)=cos(a-π/3)=1/3,
所以cos(2a-2π/3)=cos2(a-π/3)=2cos^2(a-π/3)-1=2×(1/3)^2-1=-7/9

8/9