有两个底面积相等的圆柱,一个圆柱高6DM,体积是48DM³,另一个圆柱高为5DM,体积是多少?
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有两个底面积相等的圆柱,一个圆柱高6DM,体积是48DM³,另一个圆柱高为5DM,体积是多少?
有两个底面积相等的圆柱,一个圆柱高6DM,体积是48DM³,另一个圆柱高为5DM,体积是多少?
有两个底面积相等的圆柱,一个圆柱高6DM,体积是48DM³,另一个圆柱高为5DM,体积是多少?
48÷6×5=40dm³
48除以6=8 5*8=40
6*S=48 S=8 v=s*h=8*5=40
用公式带入计算:
s=v÷h
=48÷6
=8(dm³)
v=sh
=8×5
=40(dm³)
40DM³,圆柱体的体积等于底面积乘以高
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圆柱的体积=底面积×高→底面积=体积÷高
这两个圆柱的底面积就是:48÷6=8(d㎡)
8×5=40(DM³)
.