A wire of 53 cm long is cut into two parts.The longer wire is bent to form an equilateral triangle.The shorter one is bent to form a square.If the length of each side of the square is 6 cm shorter than that of the triangle,find the respective lengths

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A wire of 53 cm long is cut into two parts.The longer wire is bent to form an equilateral triangle.The shorter one is bent to form a square.If the length of each side of the square is 6 cm shorter than that of the triangle,find the respective lengths
let X be the length of the triangle
3(X+6)+4X=53
3X+18+4X=53
7X =53-18
7X=35
X=5
the length of the shorter wire is
5cm×4＝20cm
the length of the loner wire is
(5+6) ×3= 33cm

一条长53cm的缆线截成两段。较长的一段被弯成一个等边三角形，较短的那段被弯成一个正方形。如果正方形边长比三角形的短6cm，找出可能的缆线切割方法。
设较长的一段为xcm，较短的一段为ycm，则有方程组：
x+y=53
x/3-y/4=6
解得
x=33 y=20...

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一条长53cm的缆线截成两段。较长的一段被弯成一个等边三角形，较短的那段被弯成一个正方形。如果正方形边长比三角形的短6cm，找出可能的缆线切割方法。
设较长的一段为xcm，较短的一段为ycm，则有方程组：
x+y=53
x/3-y/4=6
解得
x=33 y=20

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一条53厘米长的线切成两段。长的那条围成一个等边三角形。短的那条则围成正方形。如果正方形的边长比等边三角形的边长短6厘米，那么长的那条线和短的那条各是多少厘米？
设等边三角形边长为X厘米，正方形边长为Y厘米。
3X + 4Y = 53
X - Y = 6

解得X=11 Y=5
所以围成等边三角形的线是 3乘以11 为33厘米
...

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一条53厘米长的线切成两段。长的那条围成一个等边三角形。短的那条则围成正方形。如果正方形的边长比等边三角形的边长短6厘米，那么长的那条线和短的那条各是多少厘米？
设等边三角形边长为X厘米，正方形边长为Y厘米。
3X + 4Y = 53
X - Y = 6

解得X=11 Y=5
所以围成等边三角形的线是 3乘以11 为33厘米
围成正方形的线是 4乘以5 为20厘米
the length of the longer wire is 33cm. And the length of the shorter one is 20cm.

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一个53厘米长的线分成两个部分.把长的那部分线弯曲成一个等边三角形.较短的弯曲成一个正方形，如果的正方形的边长长比等边三角形的边长短6cm，求较长和较短的电线长度分别为多少。
设分成两部分后长的那段线的长度为x 则短的那部分长为53-x
较短的弯曲成一个正方形则正方形的边长为（53-x）/4
把长的那部分线弯曲成一个等边三角形则等边三角形的边长为x/3
正方...

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