sin^2 20+cos^2 50+sin30cos70=?
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sin^220+cos^250+sin30cos70=?sin^220+cos^250+sin30cos70=?sin^220+cos^250+sin30cos70=?=sin^220°+cos^25
sin^2 20+cos^2 50+sin30cos70=?
sin^2 20+cos^2 50+sin30cos70=?
sin^2 20+cos^2 50+sin30cos70=?
=sin^2 20°+cos^2 50°+sin(50°-20°)-sin(50°+20°)
用两角和公式
=sin^2 20°+cos^2 50°+(sin50°cos20°-sin20°cos50°)(sin50°cos20°+sin20°cos50°)
=sin^2 50°cos^2 20°-sin^2 20°cos^2 50°+sin^2 20°+cos^2 50°
用降幂公式
=[(1-cos100°)/2 *(1+cos40°)/2]-[(1-cos40°)/2 *(1+cos100°)/2]+(1-cos40°)/2 +(1-cos100°)/2
提出1/4 并整理
=1/4 *[(1-cos100°+cos40°-cos100°cos40°)-(1+cos100°-cos40°-cos100°cos40°)+2+2cos100°+2-2cos40°]
=1/4*4
=1