请用洛必达法则求导,
来源：学生作业帮助网 编辑：六六作业网 时间：2024/12/18 23:41:14
请用洛必达法则求导,请用洛必达法则求导, 请用洛必达法则求导,lim(x->0)[e^x-e^(-x)]/sinx(0/0)=lim(x->0)[e^x+e^(-x)]/cosx=2lim(
请用洛必达法则求导,
请用洛必达法则求导,
请用洛必达法则求导,
lim(x->0) [e^x- e^(-x)]/sinx (0/0)
=lim(x->0) [e^x+ e^(-x)]/cosx
= 2
lim(x->a) (x^m - a^m)/ (x^n - a^n )
case 1:m>n
lim(x->a) (x^m - a^m)/ (x^n - a^n ) (0/0)
=lim(x->a) (mx^(m-1)/ (nx^(n-1)) (0/0)
=..
=...
=lim(x->a) m(m-1)...(m-n+1)x^(m-n)/ n!
= m(m-1)...(m-n+1).a^(m-n)/ n!
= m!.a^(m-n)/[n!(m-n)!)]
case 2:m=n
lim(x->a) (x^m - a^m)/ (x^n - a^n ) =1
case 3:ma) (x^m - a^m)/ (x^n - a^n ) (0/0)
=lim(x->a) (mx^(m-1)/ (nx^(n-1)) (0/0)
=..
=...
=lim(x->a) m!/[ n(n-1).(n-m+1).x^(n-m)]
= m!(n-m)!/ [n!.a^(n-m)]
lim(x->0)x^2.e^(1/x^2)
=lim(x->0)e^(1/x^2) /(1/x^2) ( ∞/ ∞)
=lim(x->0) (-2/x^3).e^(1/x^2) /(-2/x^3)
=lim(x->0) e^(1/x^2)
-> ∞