若x,y满足(x-1)^2+(y-1)^2=4 ,则s=x+y的最小值为__________________.
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若x,y满足(x-1)^2+(y-1)^2=4,则s=x+y的最小值为__________________.若x,y满足(x-1)^2+(y-1)^2=4,则s=x+y的最小值为___________
若x,y满足(x-1)^2+(y-1)^2=4 ,则s=x+y的最小值为__________________.
若x,y满足(x-1)^2+(y-1)^2=4 ,则s=x+y的最小值为__________________.
若x,y满足(x-1)^2+(y-1)^2=4 ,则s=x+y的最小值为__________________.
s=x+y
所以x+y-s=0为所求直线方程
d(原点到直线距离)=2-s的绝对值/根号下2
因为方程可视为y=-x+s
所以最小值极为下方切点
d=2
所以s=2-2倍根号下2
依题意可知圆心为(1,1) 半径为2
所以S=-4√2 +2
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