Nicotine in Cigarettes Refer to Data Set 3 in Appendix B and use the29 measured amounts of nicotine.Construct a frequency distributionwith 8 classes beginning with a lower class limit of 0.0,and use a classwidth of 0.2.Describe the nature of the dist
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Nicotine in Cigarettes Refer to Data Set 3 in Appendix B and use the29 measured amounts of nicotine.Construct a frequency distributionwith 8 classes beginning with a lower class limit of 0.0,and use a classwidth of 0.2.Describe the nature of the dist
Nicotine in Cigarettes Refer to Data Set 3 in Appendix B and use the
29 measured amounts of nicotine.Construct a frequency distribution
with 8 classes beginning with a lower class limit of 0.0,and use a class
width of 0.2.Describe the nature of the distribution.Does the frequency
distribution appear to be roughly a normal distribution,as described in
this section?
主要那个频率不会算 怎么算的
Nicotine in Cigarettes Refer to Data Set 3 in Appendix B and use the29 measured amounts of nicotine.Construct a frequency distributionwith 8 classes beginning with a lower class limit of 0.0,and use a classwidth of 0.2.Describe the nature of the dist
香烟中的尼古丁是指数据集3附录B和使用
29个测量量的尼古丁.构建一个频率分布
8班开始与下层0的限制,并使用一个类
宽度0.2.描述分布的性质.如此的频率
分布似乎是大致呈正态分布,如
这一部分?
频率就是数据落在某一区间内的个数比数据的总数。根据你的问题,将数据落在[0.0,0.2),[0.2,0.4),[0.4,0.6),[0.6,0.8),[0.8,1.0),[1.0,1.2),[1.2,1.4),[1.4,1.6]各区间内的数据数量统计出来,再和总的数据数29之比就是数据落在各个区间内的频率。...
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频率就是数据落在某一区间内的个数比数据的总数。根据你的问题,将数据落在[0.0,0.2),[0.2,0.4),[0.4,0.6),[0.6,0.8),[0.8,1.0),[1.0,1.2),[1.2,1.4),[1.4,1.6]各区间内的数据数量统计出来,再和总的数据数29之比就是数据落在各个区间内的频率。
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是不一定的2013年9月26日8时29分46秒