求∫dy/(2sin(y/2))=-∫sin(x/2)dxps：原来的问题是求解微分方程dy/dx+cos(x-y)/2=cos(x+y)/2,求解微分方程dy/dx+cos((x-y)/2)=(cos(x+y)/2),原来那个少打了两个括号

设函数 y=sin×2+2× 求dy sin(x^2+y^2)=x,求dy xy-sin(πy^2)=0 求dy/dx x=sin(y/x)+e^2 求dy/dx y=sin^2 {x/(x+1)} 求dy y=sin(x^2),求dy/d(x^3) y=e^sin(x^2+根号x),求dy y=sin(x^2+1) 求dy请指示 y=sin(x^3),求dy/d(x^2) y = x^2 sin 4x,求dy,求dy 求该函数对x的导数 y=∫ (1,-x ) sin(t^2) dt ,求dy/dx y＝∫（x 1）sin（t∧2）dt,求dy/dx y＝∫（1 -x）sin（t∧2）dt,求dy/dx y=∫(1→t)e^(-t^2*s^2)ds,求dy/dt 求dy/dx,y=∫sin(t^2)dt由1/x积到根号x y=sin[sin(x^2)] 则dy/dx=?求详解 求∫dy/(2sin(y/2))=-∫sin(x/2)dxps：原来的问题是求解微分方程dy/dx+cos(x-y)/2=cos(x+y)/2,求解微分方程dy/dx+cos((x-y)/2)=(cos(x+y)/2),原来那个少打了两个括号 y=x*sin(lnx) 求dy