设x∈【0,π/2】,f(x)=sin(cosx),g(x)=cos(sinx),把0,1,f(x)的最大值和g(x)的最小值按由小到大的顺序排列起来应为（）A.0＜f(x)的最大值＜g(x)的最小值＜1B.g(x)的最小值＜0＜f(x)的最大值＜1C.f(x)的最大值

设函数 f(x)=sin(2x+y),(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f x=SIN(2X+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+ φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+ φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(0 设f(x)=sin(cosx),(0 设f(X)=sin(cosX),(0 设f(x)=(-x^2+x+1)e^x,证明当θ∈[0,π/2]时,|f(cosθ)-f(sinθ)| 设函数f(x)=cos(2x+π/3)+sin^2x-1/2,当x∈[0,π]时,f(x)的值域为 设f(x)={sinπx(x